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6x^2+72x-170=-2
We move all terms to the left:
6x^2+72x-170-(-2)=0
We add all the numbers together, and all the variables
6x^2+72x-168=0
a = 6; b = 72; c = -168;
Δ = b2-4ac
Δ = 722-4·6·(-168)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-96}{2*6}=\frac{-168}{12} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+96}{2*6}=\frac{24}{12} =2 $
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